(UPSC CSAT – 2023)
- 230
- 225
- 224
- 221
Solution: Ans.(2)
To be (p+q)(r+s) greatest, (p+q) and (r+s) both should be greatest
So p, q, r and s must be 9, 8, 7 and 6 not necessary in same order.
As we know the sum of all 4 numbers remain constant, so to make product maximum the two number’s difference should be minimum
So (9+6)(8+7) would be greatest
(9+6)(8+7) = 15×15 = 225
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